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90x-x^2=180
We move all terms to the left:
90x-x^2-(180)=0
We add all the numbers together, and all the variables
-1x^2+90x-180=0
a = -1; b = 90; c = -180;
Δ = b2-4ac
Δ = 902-4·(-1)·(-180)
Δ = 7380
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7380}=\sqrt{36*205}=\sqrt{36}*\sqrt{205}=6\sqrt{205}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(90)-6\sqrt{205}}{2*-1}=\frac{-90-6\sqrt{205}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(90)+6\sqrt{205}}{2*-1}=\frac{-90+6\sqrt{205}}{-2} $
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